PKR ELECTRICAL ENGINEERING
ELECTRICAL INTERVIEW QUESTIONS & ANSWERS PART-2
11. State Thevenin’sTheorem
According to thevenin’stheorem, the current flowing through a load resistanceConnected across any two terminals of a linear active bilateral network is the ratio open circuit voltage (i.e. the voltage across the two terminals when RL is removed) and sum of load resistance and internal resistance of the network.
It is given by Voc / (Ri+ RL).
PKR ELECTRICAL ENGINEERING
12. State Maximum power transfer theorem
The Maximum power transfer theorem explains about the load that a resistance will extract from the network. This includes the maximum power from the network and in this case the load resistance is being is equal to the resistance of the network and it also allows the resistance to be equal to the resistance of the network. This resistance can be viewed by the output terminals and the energy sources can be removed by leaving the internal resistance behind.
PKR ELECTRICAL ENGINEERING
13. Explain different losses in a transformer.
There are two types of losses occurring in transformer:
• Constant losses or Iron losses:
The losses that occur in the core are known as core losses or iron losses.
Two types of iron losses are:-
eddy current loss-Hysteresis loss.
These losses depend upon the supply voltage, frequency, core material and its construction. As long as supply voltage and frequency is constant, these losses remain the same whether the transformer is loaded or not. These are also known as constant losses.
• Variable losses or copper losses:
when the transformer is loaded, current flows in primary and secondary windings, there is loss of electrical energy due to the resistance of the primary winding, and secondary winding and they are called variable losses. These losses depend upon the loading conditions of the transformers. Therefore, these losses are also called as variable losses
PKR ELECTRICAL ENGINEERING
14. Explain different types of D.C motors? Give their applications
Different type of DC motors and their applications are as follows:-
• Shunt motors: It has a constant speed though its starting torque is not very high. Therefore, it is suitable for constant speed drive, where high starting torque is not required such as pumps, blowers, fan, lathe machines, tools, belt or chain conveyor etc.
• Service motors: It has high starting torque & its speed is inversely proportional to the loading conditions i.e. when lightly loaded, the speed is high and when heavily loaded, it is low. Therefore, motor is used in lifts, cranes, traction work, coal loader and coal cutter in coalmines etc.
• Compound motors: It also has high starting torque and variable speed. Its advantage is, it can run at NIL loads without any danger. This motor will therefore find its application in loads having high inertia load or requiring high intermittent torque such as elevators, conveyor, rolling mill, planes, presses, shears and punches, coal cutter and winding machines etc
PKR ELECTRICAL ENGINEERING
15. Explain the process of commutation in a dc machine. Explain what are inter-poles and why they are required in a dc machine.
Commutation: It is phenomenon when an armature coil moves under the influence of one pole-pair; it carries constant current in one direction. As the coil moves into the influence of the next pole-pair, the current in it must reverse.
This reversal of current in a coil is called commutation. Several coils undergo commutation simultaneously. The reversal of current is opposed by the static coil emfand therefore must be aided in some fashion for smooth current reversal, which otherwise would result in sparking at the brushes.
The aiding emfis dynamically induced into the coils undergoing commutation by means of compolesor interpoles, which are series excited by the armature current. These are located in the interpolarregion of the main poles and therefore influence the armature coils only when these undergo commutation.
PKR ELECTRICAL ENGINEERING
16. Comment on the working principle of operation of a single-phase transformer.
Working principle of operation of a single-phase transformer can be explained asAn AC supply passes through the primary winding, a current will start flowing in the primary winding. As a result, the flux is set. This flux is linked with primary and secondary windings. Hence, voltage is induced in both the windings. Now, when the load is connected to the secondary side, the current will start flowing in the load in the secondary winding, resulting in the flow of additional current in the secondary winding. Hence, according to Faraday’s laws of electromagnetic induction, emfwill be induced in both the windings.
The voltage induced in the primary winding is due to its self inductance and known as self induced emfand according to Lenze’slaw it will oppose the cause i.e. supply voltage hence called as back emf. The voltage induced in secondary coil is known as mutually induced voltage. Hence, transformer works on the principle of electromagnetic induction.
PKR ELECTRICAL ENGINEERING
17. Define the following terms:-Reliability, Maximum demand, Reserve-generating capacity,Availability (operational).
Reliability:
It is the capacity of the power system to serve all power demands without failure over long periods.
Maximum Demand:
It is maximum load demand required in a power station during a given period.
Reserve generating capacity:
Extra generation capacity installed to meet the need of scheduled downtimes for preventive maintenance is called reserve-generating capacity.
Availability:
As the percentage of the time a unit is available to produce power whether needed by the system or not.
PKR ELECTRICAL ENGINEERING
18. Mention the disadvantages of low power factor? How can it be improved?
Disadvantages of low power factor:
• Line losses are 1.57 times unity power factor.
• Larger generators and transformers are required.
• Low lagging power factor causes a large voltage drop, hence extra regulation equipment is required to keep voltage drop within prescribed limits.
• Greater conductor size: To transmit or distribute a fixed amount of power at fixed voltage, the conductors will have to carry more current at low power factor. This requires a large conductor size.
PKR ELECTRICAL ENGINEERING
19. State the methods of improving power factor?
Methods of improving power factor:
• By connecting static capacitors in parallel with the load operating at lagging power factor.
• A synchronous motor takes a leading current when over excited and therefore behaves like a capacitor.
• By using phase advancers to improve the power factor of induction motors. It provides exciting ampere turns to the rotor circuit of the motor. By providing more ampere-turns than required, the induction motor can be made to operate on leading power factor like an overexcited synchronous motor.
PKR ELECTRICAL ENGINEERING
20. State the factors, for the choice of electrical system for an aero turbine.
The choice of electrical system for an aero turbine is guided by three factors:
• Type of electrical output: dc, variable-frequency ac, and constant-frequency ac.
• Aero turbine rotational speed: constant speed with variable blade pitch, nearly constant speed with simpler pitch-changing mechanism or variable speed with fixed pitch blades.
• Utilization of electrical energy output: in conjunction with battery or other form of storage, or interconnection with power grid.
PKR ELECTRICAL ENGINEERING
21. What are the advantages of VSCF wind electrical system?
Advantages of VSCF wind electrical system are:• No complex pitch changing mechanism is needed.• Aero turbine always operates at maximum efficiency point.• Extra energy in the high wind speed region of the speed –duration curve can be extracted• Significant reduction in aerodynamic stresses, which are associated with constant –speed operation.
PKR ELECTRICAL ENGINEERING
22. Explain the terms real power, apparent power and reactive power for ac circuits and also the units used.
• Real Power:
It is the product of voltage, current and power factor
i.e. P = V I cosj and basic unit of real power is watt.
i.e. Expressed as W or kW.
• Apparent power:
It is the product of voltage and current. Apparent power = V I and basic unit of apparent power is volt-ampere. Expressed as VA or KVA.
• Reactive Power:
It is the product of voltage, current and sine of angle between the voltage and current i.e. Reactive power = voltage X current X sinjor Reactive power = V I sin j and has no other unit but expressed in VAR or KVAR.
PKR ELECTRICAL ENGINEERING
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https://www.youtube.com/channel/UC4_D50vMu1wbQrPaLFYo6Eg https://www.youtube.com/channel/UC4_D50vMu1wbQrPaLFYo6Eg RRB JE, SSC AE/JE UPSSSC JE, SSC JE, CIVIL ENGINEERING MCQs, ELECTICAL ENGINEERING MCQs, preavious year quesion papers, dmrc, lmrc, drdo,rrb ntpc, ntpc, pgcil, dsssb, states board, GATE IES EE, ESE, ECE, ME, CE, IT & CS EXAM MATERIALS & OLD PAPERS Electrical Engineering https://t.me/pravendrarajpoot Daily news & current affairs in hindi & english fully updated Daily current affairs https://t.me/newsdailypkr Engineering Discussion group for your upcoming exams, you can ask your any query regarding your problem,๐๐๐ https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA PKR ELECTRICAL ENGINEERING I am sure this is the best place for you guys subscribe and get success IF YOU WANT TO JOIN ME ON TELEGRAM FOR PDF @newsdailypkr AE/JE EE, ESE, ECE, ME, CE, IT & CS EXAM MATERIALS & OLD PAPERS Electrical Engineering https://t.me/pravendrarajpoot facebook page:- Pravendra Kumar Rajpoot https://t.me/newsdailypkr https://chat.whatsapp.com/5AS7dNFTP4H4vVsiWsqHrT https://t.me/srk50 https://t.me/pravendrarajpoot https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA https://t.me/pravendrarajpoot Daily news & current affairs in hindi & english fully updated Daily current affairs https://t.me/newsdailypkr Engineering Discussion group for your upcoming exams, you can ask your any query regarding your problem,๐๐๐ https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA PKR ELECTRICAL ENGINEERING I am sure this is the best place for you guys subscribe and get success IF YOU WANT TO JOIN ME ON TELEGRAM FOR PDF @newsdailypkr AE/JE EE, ESE, ECE, ME, CE, IT & CS EXAM MATERIALS & OLD PAPERS Electrical Engineering https://t.me/pravendrarajpoot facebook page:- Pravendra Kumar Rajpoot https://t.me/newsdailypkr https://chat.whatsapp.com/5AS7dNFTP4H4vVsiWsqHrT https://t.me/srk50 https://t.me/pravendrarajpoot https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA
ELECTRICAL INTERVIEW QUESTIONS & ANSWERS PART-2
11. State Thevenin’sTheorem
According to thevenin’stheorem, the current flowing through a load resistanceConnected across any two terminals of a linear active bilateral network is the ratio open circuit voltage (i.e. the voltage across the two terminals when RL is removed) and sum of load resistance and internal resistance of the network.
It is given by Voc / (Ri+ RL).
PKR ELECTRICAL ENGINEERING
12. State Maximum power transfer theorem
The Maximum power transfer theorem explains about the load that a resistance will extract from the network. This includes the maximum power from the network and in this case the load resistance is being is equal to the resistance of the network and it also allows the resistance to be equal to the resistance of the network. This resistance can be viewed by the output terminals and the energy sources can be removed by leaving the internal resistance behind.
PKR ELECTRICAL ENGINEERING
13. Explain different losses in a transformer.
There are two types of losses occurring in transformer:
• Constant losses or Iron losses:
The losses that occur in the core are known as core losses or iron losses.
Two types of iron losses are:-
eddy current loss-Hysteresis loss.
These losses depend upon the supply voltage, frequency, core material and its construction. As long as supply voltage and frequency is constant, these losses remain the same whether the transformer is loaded or not. These are also known as constant losses.
• Variable losses or copper losses:
when the transformer is loaded, current flows in primary and secondary windings, there is loss of electrical energy due to the resistance of the primary winding, and secondary winding and they are called variable losses. These losses depend upon the loading conditions of the transformers. Therefore, these losses are also called as variable losses
PKR ELECTRICAL ENGINEERING
14. Explain different types of D.C motors? Give their applications
Different type of DC motors and their applications are as follows:-
• Shunt motors: It has a constant speed though its starting torque is not very high. Therefore, it is suitable for constant speed drive, where high starting torque is not required such as pumps, blowers, fan, lathe machines, tools, belt or chain conveyor etc.
• Service motors: It has high starting torque & its speed is inversely proportional to the loading conditions i.e. when lightly loaded, the speed is high and when heavily loaded, it is low. Therefore, motor is used in lifts, cranes, traction work, coal loader and coal cutter in coalmines etc.
• Compound motors: It also has high starting torque and variable speed. Its advantage is, it can run at NIL loads without any danger. This motor will therefore find its application in loads having high inertia load or requiring high intermittent torque such as elevators, conveyor, rolling mill, planes, presses, shears and punches, coal cutter and winding machines etc
PKR ELECTRICAL ENGINEERING
15. Explain the process of commutation in a dc machine. Explain what are inter-poles and why they are required in a dc machine.
Commutation: It is phenomenon when an armature coil moves under the influence of one pole-pair; it carries constant current in one direction. As the coil moves into the influence of the next pole-pair, the current in it must reverse.
This reversal of current in a coil is called commutation. Several coils undergo commutation simultaneously. The reversal of current is opposed by the static coil emfand therefore must be aided in some fashion for smooth current reversal, which otherwise would result in sparking at the brushes.
The aiding emfis dynamically induced into the coils undergoing commutation by means of compolesor interpoles, which are series excited by the armature current. These are located in the interpolarregion of the main poles and therefore influence the armature coils only when these undergo commutation.
PKR ELECTRICAL ENGINEERING
16. Comment on the working principle of operation of a single-phase transformer.
Working principle of operation of a single-phase transformer can be explained asAn AC supply passes through the primary winding, a current will start flowing in the primary winding. As a result, the flux is set. This flux is linked with primary and secondary windings. Hence, voltage is induced in both the windings. Now, when the load is connected to the secondary side, the current will start flowing in the load in the secondary winding, resulting in the flow of additional current in the secondary winding. Hence, according to Faraday’s laws of electromagnetic induction, emfwill be induced in both the windings.
The voltage induced in the primary winding is due to its self inductance and known as self induced emfand according to Lenze’slaw it will oppose the cause i.e. supply voltage hence called as back emf. The voltage induced in secondary coil is known as mutually induced voltage. Hence, transformer works on the principle of electromagnetic induction.
PKR ELECTRICAL ENGINEERING
17. Define the following terms:-Reliability, Maximum demand, Reserve-generating capacity,Availability (operational).
Reliability:
It is the capacity of the power system to serve all power demands without failure over long periods.
Maximum Demand:
It is maximum load demand required in a power station during a given period.
Reserve generating capacity:
Extra generation capacity installed to meet the need of scheduled downtimes for preventive maintenance is called reserve-generating capacity.
Availability:
As the percentage of the time a unit is available to produce power whether needed by the system or not.
PKR ELECTRICAL ENGINEERING
18. Mention the disadvantages of low power factor? How can it be improved?
Disadvantages of low power factor:
• Line losses are 1.57 times unity power factor.
• Larger generators and transformers are required.
• Low lagging power factor causes a large voltage drop, hence extra regulation equipment is required to keep voltage drop within prescribed limits.
• Greater conductor size: To transmit or distribute a fixed amount of power at fixed voltage, the conductors will have to carry more current at low power factor. This requires a large conductor size.
PKR ELECTRICAL ENGINEERING
19. State the methods of improving power factor?
Methods of improving power factor:
• By connecting static capacitors in parallel with the load operating at lagging power factor.
• A synchronous motor takes a leading current when over excited and therefore behaves like a capacitor.
• By using phase advancers to improve the power factor of induction motors. It provides exciting ampere turns to the rotor circuit of the motor. By providing more ampere-turns than required, the induction motor can be made to operate on leading power factor like an overexcited synchronous motor.
PKR ELECTRICAL ENGINEERING
20. State the factors, for the choice of electrical system for an aero turbine.
The choice of electrical system for an aero turbine is guided by three factors:
• Type of electrical output: dc, variable-frequency ac, and constant-frequency ac.
• Aero turbine rotational speed: constant speed with variable blade pitch, nearly constant speed with simpler pitch-changing mechanism or variable speed with fixed pitch blades.
• Utilization of electrical energy output: in conjunction with battery or other form of storage, or interconnection with power grid.
PKR ELECTRICAL ENGINEERING
21. What are the advantages of VSCF wind electrical system?
Advantages of VSCF wind electrical system are:• No complex pitch changing mechanism is needed.• Aero turbine always operates at maximum efficiency point.• Extra energy in the high wind speed region of the speed –duration curve can be extracted• Significant reduction in aerodynamic stresses, which are associated with constant –speed operation.
PKR ELECTRICAL ENGINEERING
22. Explain the terms real power, apparent power and reactive power for ac circuits and also the units used.
• Real Power:
It is the product of voltage, current and power factor
i.e. P = V I cosj and basic unit of real power is watt.
i.e. Expressed as W or kW.
• Apparent power:
It is the product of voltage and current. Apparent power = V I and basic unit of apparent power is volt-ampere. Expressed as VA or KVA.
• Reactive Power:
It is the product of voltage, current and sine of angle between the voltage and current i.e. Reactive power = voltage X current X sinjor Reactive power = V I sin j and has no other unit but expressed in VAR or KVAR.
PKR ELECTRICAL ENGINEERING
www.EngineeringBooksPdf
https://www.youtube.com/channel/UC4_D50vMu1wbQrPaLFYo6Eg https://www.youtube.com/channel/UC4_D50vMu1wbQrPaLFYo6Eg RRB JE, SSC AE/JE UPSSSC JE, SSC JE, CIVIL ENGINEERING MCQs, ELECTICAL ENGINEERING MCQs, preavious year quesion papers, dmrc, lmrc, drdo,rrb ntpc, ntpc, pgcil, dsssb, states board, GATE IES EE, ESE, ECE, ME, CE, IT & CS EXAM MATERIALS & OLD PAPERS Electrical Engineering https://t.me/pravendrarajpoot Daily news & current affairs in hindi & english fully updated Daily current affairs https://t.me/newsdailypkr Engineering Discussion group for your upcoming exams, you can ask your any query regarding your problem,๐๐๐ https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA PKR ELECTRICAL ENGINEERING I am sure this is the best place for you guys subscribe and get success IF YOU WANT TO JOIN ME ON TELEGRAM FOR PDF @newsdailypkr AE/JE EE, ESE, ECE, ME, CE, IT & CS EXAM MATERIALS & OLD PAPERS Electrical Engineering https://t.me/pravendrarajpoot facebook page:- Pravendra Kumar Rajpoot https://t.me/newsdailypkr https://chat.whatsapp.com/5AS7dNFTP4H4vVsiWsqHrT https://t.me/srk50 https://t.me/pravendrarajpoot https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA https://t.me/pravendrarajpoot Daily news & current affairs in hindi & english fully updated Daily current affairs https://t.me/newsdailypkr Engineering Discussion group for your upcoming exams, you can ask your any query regarding your problem,๐๐๐ https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA PKR ELECTRICAL ENGINEERING I am sure this is the best place for you guys subscribe and get success IF YOU WANT TO JOIN ME ON TELEGRAM FOR PDF @newsdailypkr AE/JE EE, ESE, ECE, ME, CE, IT & CS EXAM MATERIALS & OLD PAPERS Electrical Engineering https://t.me/pravendrarajpoot facebook page:- Pravendra Kumar Rajpoot https://t.me/newsdailypkr https://chat.whatsapp.com/5AS7dNFTP4H4vVsiWsqHrT https://t.me/srk50 https://t.me/pravendrarajpoot https://t.me/joinchat/JObxeA7n6S4qvnegrGhTgA